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(PHP 4, PHP 5)
gzfile — Read entire gz-file into an array
Diese Funktion entspricht weitgehend readgzfile(), gibt die Datei aber in einem Array zurück.
Der Dateiname.
Sie können diesen optionalen Parameter auf 1 setzen wenn Sie die Datei auch im include_path suchen lassen wollen.
Ein Array das die Zeilen der Datei als Elemente enthält.
Beispiel #1 gzfile() example
<?php
$lines = gzfile('somefile.gz');
foreach ($lines as $line) {
echo $line;
}
?>
This function is not binary safe. (intentionally, or not, that's the question :)
In PHP4.4.1 I noticed that gzfile only reads up to 8190 bytes per line. I had a 20K SQL query that was cut into 3 parts - and wondered why the SQL server complained.
Reading an uncompressed file with the file() command works as expected.
A quicker way to load a gziped file in a string :
<?php
function gzfile_get_contents($filename, $use_include_path = 0)
{
//File does not exist
if( !@file_exists($filename) )
{ return false; }
//Read and imploding the array to produce a one line string
$data = gzfile($filename, $use_include_path);
$data = implode($data);
return $data;
}
?>
This works similar to gzfile() but it returns the file in a string instead of an array and doesn't write it to stdout compared to readgzfile.
Note: unlike the usual file-functions filesize won't work here, since the length-parameter of gzread refers to the uncompressed length, while filesize returns the size of the compressed file.
<?php
function gzfile_get_contents($filename, $use_include_path = 0) {
$file = @gzopen($filename, 'rb', $use_include_path);
if ($file) {
$data = '';
while (!gzeof($file)) {
$data .= gzread($file, 1024);
}
gzclose($file);
}
return $data;
}
?>
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