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(PHP 4 >= 4.0.1, PHP 5)
imagepalettecopy — Copy the palette from one image to another
imagepalettecopy() copies the palette from the source image to the destination image.
The destination image resource.
The source image resource.
Es wird kein Wert zurückgegeben.
Beispiel #1 imagepalettecopy() example
<?php
// Create two palette images
$palette1 = imagecreate(100, 100);
$palette2 = imagecreate(100, 100);
// Allocate the background to be
// green in the first palette image
$green = imagecolorallocate($palette1, 0, 255, 0);
// Copy the palette from image 1 to image 2
imagepalettecopy($palette2, $palette1);
// Since the palette is now copied we can use the
// green color allocated to image 1 without using
// imagecolorallocate() twice
imagefilledrectangle($palette2, 0, 0, 99, 99, $green);
// Output image to the browser
header('Content-type: image/png');
imagepng($palette2);
imagedestroy($palette1);
imagedestroy($palette2);
?>
actually it doesn't "copy" the palette exactly. It copys the colors from the source palette to the destination image. the palette you end up with in the destination image will be "same colors different order". If you want an EXACT palette copy (at the expense of messing up your image if you aren't careful), then use this code:
<?
// this is a drop-in replacement for imagepalettecopy, except that it make NO attempt to modifiy any of the
// colors in the dest image, just the palette. The result? if you're palette's aren't very similar, the image will look completely different, and likely terrible!
function imagepalettecopy_exact ( $dst_img, $src_img) {
for( $c = 0 ; $c < imagecolorstotal($src_img); $c++) {
$col = imagecolorsforindex($src_img,$c); //get color at index 'c' in the color table
imagecolorset($dst_img,$c,$col[red],$col[green],$col[blue]); //set color at index 'c' to $col in the $dst_image
}
}
?>
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