Diese Seite bei php.net
The PHP manual text and comments are covered by the Creative Commons Attribution 3.0 License © the PHP Documentation Group - Impressum - mail("TO:Reinhard Neidl",...)
(PHP 4, PHP 5)
get_included_files — Liefert ein Array mit den Namen der includierten Dateien
Gibt die Namen aller Dateien zurück die mit include(), include_once(), require() oder require_once() eingebunden wurden.
Gibt ein Array mit Dateinamen zurück.
Das ursprünglich aufgerufene Skript wird auch als includierte Datei angesehen und damit zusammen mit den Namen der tatäschlich mit include() etc. eingebundenen Dateien zurückgegeben.
Dateien die mehrfach eingebunden werden erscheinen nur einfach im Ergebnisarray.
| Version | Beschreibung |
|---|---|
| 4.0.1 | Bis einschließlich PHP 4.0.1 nahm diese Funktion an dass die includierten Dateien grundsätzlich auf .php enden und ignorierte Dateien mit anderen Endungen. Das zurückgegebene Array war assoziativ und enthielt nur mit include() oder include_once() eingebunden wurden. |
Beispiel #1 get_included_files()Beispiel
<?php
// Diese Datei ist abc.php
include 'test1.php';
include_once 'test2.php';
require 'test3.php';
require_once 'test4.php';
$included_files = get_included_files();
foreach ($included_files as $filename) {
echo "$filename\n";
}
?>
Das oben gezeigte Beispiel erzeugt folgende Ausgabe:
abc.php test1.php test2.php test3.php test4.php
Hinweis:
Dateien die über die auto_prepend_file Konfigurationsdirektive eingebunden werden sind nicht Teil des Ergebnisarrays.
If you want to get the relative path of an included file, from within itself use this function. If you ever have a include file thats path may not be static, this can save some time.
<?php
function get_current_files_path($file_name)
{
//find the current files directory
$includes = get_included_files();
$path = "";
for ($i=0; $i < count($includes); $i++)
{
$path = strstr($includes[$i], $file_name);
if ($path != false)
{
$key = $i;
break;
}
}
$path = str_replace(getcwd(), "", $includes[$key]);
$path = str_replace("\\", "/", $path);
$path = str_replace($file_name, "", $path);
$path = ltrim($path, "/");
return $path;
}
?>
If you want to avoid the filepaths, just wrap get_included_files() inside preg_replace() to get rid of path info:
<?php
$filenames = preg_replace("/\/.*\//", "", get_included_files());
?>
If you have a MAIN php script which you don't want to be included by other scripts, you could use this function. For example:
main.php:
<?php
function blockit()
{
$buf = get_included_files();
return $buf[0] != __FILE__;
}
blockit() and exit("You can not include a MAIN file as a part of your script.");
print "OK";
?>
So other script couldn't include main.php to modify its internal global vars.
Something that's not noted in the docs, if a file is included remotely and you do a get_included_files() in the include itself it will *not* return the document that included it.
ie:
test2.php (server 192.168.1.14):
<?php
include("http://192.168.1.11/test/test3.php");
?>
test3.php (server 192.168.1.11):
<?php
$files = get_included_files();
print_r($files);
?>
returns:
Array ( [0] => /var/www/localhost/htdocs/test/test3.php )
Which means you can use get_included_files() to help intercept and prevent XSS-style attacks against your code.
As is often the case, YMMV. I tried the __FILE__ and SCRIPT_FILENAME comparison and found this:
SCRIPT_FILENAME: /var/www/cgi-bin/php441
__FILE__: /raid/home/natpresch/natpresch/RAY_included.php
As an alternative:
count(get_included_files());
Gives one when the script is standalone and always more than one when the script is included.
As of PHP5, this function seems to return an array with the first index being the script all subsequent scripts are included to.
If index.php includes b.php and c.php and calls get_included_files(), the returned array looks as follows:
index.php
a.php
b.php
while in PHP<5 the array would be:
a.php
b.php
If you want to know which is the script that is including current script you can use $_SERVER['SCRIPT_FILENAME'] or any other similar server global.
If you also want to ensure current script is being included and not run independently you should evaluate following expression:
__FILE__ != $_SERVER['SCRIPT_FILENAME']
If this expression returns TRUE, current script is being included or required.
Diese Seite bei php.net